IcCookies 24 Posted October 25, 2015 Hello eveyone. So I know that if you want to create an area you would do Area fishArea = new Area(3085, 3233, 3089, 3224, 0); but what happens if I want different z values? For example, I still want the equation to be true if I'm on the x and y, but with a z value of 1 instead of 0. How would I do that?
RealEngine 24 Posted October 25, 2015 dont define it that way. use the same thing but just define new tiles so you can have a cube.
Nuclear Nezz 2105 Posted October 25, 2015 Area fishArea = new Area(3085, 3233, 3089, 3224, 0); the constructor is x1, y1, x2, y2, z so if you want it on z 1 Area fishArea = new Area(3085, 3233, 3089, 3224, 1);
RealEngine 24 Posted October 25, 2015 Area fishArea = new Area(3085, 3233, 3089, 3224, 0); the constructor is x1, y1, x2, y2, z so if you want it on z 1 Area fishArea = new Area(3085, 3233, 3089, 3224, 1); I think he wants a cube , so as long as he in an area that has verticle components? Area yourArea = new Area((new Tile(3169, 2976, 0)), (new Tile(3176, 2970, 1)));
qbots 240 Posted October 26, 2015 I think he wants a cube , so as long as he in an area that has verticle components? Area yourArea = new Area((new Tile(3169, 2976, 0)), (new Tile(3176, 2970, 1))); Or he could just use: Area(int x1, int y1, int x2, int y2) Creates a rectangular area using basic coordinates for any plane. Dont input the Z and it ignores the plane unless the API is lying to me.
RealEngine 24 Posted October 26, 2015 Or he could just use: Area(int x1, int y1, int x2, int y2) Creates a rectangular area using basic coordinates for any plane. Dont input the Z and it ignores the plane unless the API is lying to me. yeah that should totally work too. Look at all these solutions
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