Continuity with calculations.random()

[JAG98 4]

In the snippet below

Spoiler

int x = Calculations.random(1,3);
if(x==1){
    //some code
}
else{
    //some other code
}

How to continue the flow of execution? Every time onLoop will iterate, a new value gets assigned to x and the codes that get executed may change. How to ensure only one segment gets executed after the first iteration. if x ==1, only some code should get executed and shouldn't flip between some other code till a new condition doesn't trigger the change.

[CodeNinja 32]

not exactly sure if i understand you, but it sounds like you want to set x to a random number in onstart, and then dont set it again until your code is completed in the if/else statement

 

psuedo code:

onstart {
x = Calculations.random(1,3);
}

loop() {
if(x = 1) {
	if(//your code to execute) {
		x=Calculations.random(1,3);
	}
} else {
	if(//your other code to execute) {
		x=Calculations.random(1,3);
	}
}

 

Edited December 21, 2020 by CodeNinja

[una_maquina 24]

Err, not sure exactly what you need, but maybe you're looking for a "return;" ? This will go back to the beginning without running anything else.