Hide/Show paint

[abdulr 0]

how do i have a rectangle area on my screen - if clicked either hide or show the onPaint function

[Nex 2516]

boolean hidePaint = false;

Rectangle rect = new Rectangle(296, 444, 200, 16);
Rectangle closePaint = rect;
Rectangle openPaint = rect;
Point p;

public void onMouse(MouseEvent e) {
        p = e.getPoint();
        if (closePaint.contains(p) && !hidePaint) {
        	hidePaint = true;
        } else if (openPaint.contains(p) && hidePaint) {
        	hidePaint = false;
        }
    }

@Override
	public void onPaint(Graphics g) {
		if (!hidePaint) {
			.......
		}
        	if (hidePaint) {
        		.....
        	}
    }

 

[abdulr 0]

thank you

[Evil Bob 5]

3 hours ago, Nex said:

boolean hidePaint = false;

Rectangle rect = new Rectangle(296, 444, 200, 16);
Rectangle closePaint = rect;
Rectangle openPaint = rect;
Point p;

public void onMouse(MouseEvent e) {
        p = e.getPoint();
        if (closePaint.contains(p) && !hidePaint) {
        	hidePaint = true;
        } else if (openPaint.contains(p) && hidePaint) {
        	hidePaint = false;
        }
    }

@Override
	public void onPaint(Graphics g) {
		if (!hidePaint) {
			.......
		}
        	if (hidePaint) {
        		.....
        	}
    }

 

 

If the rectangle for closing and opening the paint points to the same memory address, you could take advantage of this and cut the number of lines of code in half.

	private boolean hidePaint = false;
	private final Rectangle PAINT_BUTTON = new Rectangle(296, 444, 200, 16);

	@Override
	public void onMouse(MouseEvent e) {
		if (PAINT_BUTTON.contains(e.getPoint()))
			hidePaint = !hidePaint;
	}

	@Override
	public void onPaint(Graphics g) {
		if (!hidePaint) {
			// ...
		} else {
			// ...
		}
	}