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  • Get number from string (like ""Wintertodt's Energy: 35%") using regex


    distraction
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    Someone asked about this in discord earlier today, and I helped them get it working. I figured I would post it here in case anyone else has the same issue. Basically, he needed to get the % value from the string "Wintertodt's Energy: 35%". To do this, I used a regular expression to grab only the numbers from the string, and then used `parseInt` on the result. Here is an example on how to do this.

            // this should be replaced with whatever code fetches the string
            String str = "Wintertodt's Energy: 35%";
            // create the regex pattern to find numbers
            Pattern ints = Pattern.compile("\\d+");
            // run the regex pattern on the string we want to parse the numbers from
            Matcher makeMatch = ints.matcher(str);
            makeMatch.find();
    
            // set the result
            String result = makeMatch.group();
            // this should print 35 in your console (note that 35 is actually still a string at this point)
            log(result);
            // parse the number from the result string to convert it to the right data type (int)
            int integerValue = Integer.parseInt(result);
            // this should print 35 in your console (note that 35 is an int here, which is why we have to do integerValue+"" to get it to log since log takes in a string)
            log(integerValue+"");
    

    Once you have `integerValue`, you can do things like `if (integerValue > 50)` or `if (integerValue == 100)`. Let me know if you have any questions or suggestions on an easier way to do this.

     

    Here are the required imports for the code above

    import java.util.regex.Matcher;
    import java.util.regex.Pattern;
    
    Edited by distraction
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